Files
advent-of-code-go/2019/day07/part1/main.go
T
2020-11-27 02:53:18 -05:00

201 lines
6.6 KiB
Go

/*
Intcode struct is defined within this file
MakePermutations is in the util package as that will likely be reused
*/
package main
import (
"github.com/alexchao26/advent-of-code-go/util"
"fmt"
"log"
"strconv"
"strings"
)
func main() {
// read the input file, modify it to a slice of numbers
inputFile := util.ReadFile("../input.txt")
splitStrings := strings.Split(inputFile, ",")
inputNumbers := make([]int, len(splitStrings))
for i, v := range splitStrings {
inputNumbers[i], _ = strconv.Atoi(v)
}
// Make perms via a util function
perms := util.MakePermutations([]int{0, 1, 2, 3, 4})
// iterate over all perms and run through a single pass of the Amps
// if the final output (from Amp E) is higher, update the highestOutput variable
highestOutput := 0
for _, perm := range *perms {
// initialize 5 computers
ampA := MakeComputer(inputNumbers, perm[0])
ampB := MakeComputer(inputNumbers, perm[1])
ampC := MakeComputer(inputNumbers, perm[2])
ampD := MakeComputer(inputNumbers, perm[3])
ampE := MakeComputer(inputNumbers, perm[4])
// first input (besides phase setting) to Amp A is zero
ampA.Step(0)
ampB.Step(ampA.LastOutput)
ampC.Step(ampB.LastOutput)
ampD.Step(ampC.LastOutput)
ampE.Step(ampD.LastOutput)
if ampE.LastOutput > highestOutput {
highestOutput = ampE.LastOutput
}
}
// print highest output found
fmt.Printf("Highest output is %v\n", highestOutput)
}
/*
Intcode is an OOP approach *************************************************
MakeComputer is equivalent to the constructor
Step takes in an input int and updates properties in the computer:
- InstructionIndex: where to read the next instruction from
- LastOutput, what the last opcode 4 outputted
- PuzzleIndex based if the last instruction modified the puzzle at all
****************************************************************************/
type Intcode struct {
PhaseSetting int // initial input: ID or number used to "prime"/setup the comp
PuzzleInput []int // file/puzzle input parsed into slice of ints
InstructionIndex int // stores the index where the next instruction is
LastOutput int // last output from an opcode 4
}
// MakeComputer initializes a new comp
func MakeComputer(PuzzleInput []int, PhaseSetting int) Intcode {
puzzleInputCopy := make([]int, len(PuzzleInput))
copy(puzzleInputCopy, PuzzleInput)
comp := Intcode{
PhaseSetting,
puzzleInputCopy,
0,
0,
}
// Prime the computer by running its initial phase setting through it
// This will update the comp's InstructionIndex so it's pointing to the next command
// will also update the PuzzleInput itself via opcode 3's insert
// AND will run the computer until it asks for the next input, _comp is now primed_
comp.Step(PhaseSetting)
return comp
}
// Step will read the next 4 values in the input `sli` and make updates
// according to the opcodes
func (comp *Intcode) Step(input int) int {
// read the instruction, opcode and the indexes where the params point to
opcode, paramIndexes := comp.GetOpCodeAndIndexes()
switch opcode {
case 99: // 99: Terminates program
// fmt.Println("Terminating...")
return input
case 1: // 1: Add next two paramIndexes, store in third
comp.PuzzleInput[paramIndexes[2]] = comp.PuzzleInput[paramIndexes[0]] + comp.PuzzleInput[paramIndexes[1]]
comp.InstructionIndex += 4
return comp.Step(input)
case 2: // 2: Multiply next two and store in third
comp.PuzzleInput[paramIndexes[2]] = comp.PuzzleInput[paramIndexes[0]] * comp.PuzzleInput[paramIndexes[1]]
comp.InstructionIndex += 4
return comp.Step(input)
case 3: // 3: Takes one input and saves it to position of one parameter
// check if input has already been used (i.e. input == -1)
// if it's been used, return the LastOutput
// NOTE: making a big assumption that -1 will never be an input...
if input == -1 {
return comp.LastOutput
}
// otherwise use the input, then recurse with a -1 to signal the initial input has been used
comp.PuzzleInput[paramIndexes[0]] = input
comp.InstructionIndex += 2
return comp.Step(-1)
case 4: // 4: outputs its input value
// set LastOutput of the computer & log it
comp.LastOutput = comp.PuzzleInput[paramIndexes[0]]
// fmt.Printf("Opcode 4 output: %v\n", comp.LastOutput)
comp.InstructionIndex += 2
// continue running until terminates or asks for another input
return comp.Step(input)
// 5: jump-if-true: if first param != 0, move pointer to second param, else nothing
case 5:
if comp.PuzzleInput[paramIndexes[0]] != 0 {
comp.InstructionIndex = comp.PuzzleInput[paramIndexes[1]]
} else {
comp.InstructionIndex += 3
}
return comp.Step(input)
// 6: jump-if-false, if first param == 0 then set instruction pointer to 2nd param, else nothing
case 6:
if comp.PuzzleInput[paramIndexes[0]] == 0 {
comp.InstructionIndex = comp.PuzzleInput[paramIndexes[1]]
} else {
comp.InstructionIndex += 3
}
return comp.Step(input)
// 7: less-than, if param1 < param2 then store 1 in postion of 3rd param, else store 0
case 7:
if comp.PuzzleInput[paramIndexes[0]] < comp.PuzzleInput[paramIndexes[1]] {
comp.PuzzleInput[paramIndexes[2]] = 1
} else {
comp.PuzzleInput[paramIndexes[2]] = 0
}
comp.InstructionIndex += 4
return comp.Step(input)
// 8: equals, if param1 == param2 then set position of 3rd param to 1, else store 0
case 8:
if comp.PuzzleInput[paramIndexes[0]] == comp.PuzzleInput[paramIndexes[1]] {
comp.PuzzleInput[paramIndexes[2]] = 1
} else {
comp.PuzzleInput[paramIndexes[2]] = 0
}
comp.InstructionIndex += 4
return comp.Step(input)
default:
log.Fatal("Error: unknown opcode: ", opcode)
}
// this should never be called b/c switch statement will always return
return -1
}
/*
GetOpCodeAndIndexes will parse the instruction at comp.PuzzleInput[comp.InstructionIndex]
- opcode will be the left two digits, mod by 100 will get that
- rest of instructions will be grabbed via mod 10
- these also have to be parsed for the
*/
func (comp *Intcode) GetOpCodeAndIndexes() (int, [3]int) {
instruction := comp.PuzzleInput[comp.InstructionIndex]
// opcode is the lowest two digits, so mod by 100
opcode := instruction % 100
instruction /= 100
// assign the indexes that need to be read by reading the parameter modes
var paramIndexes [3]int
for i := 1; i <= 3 && comp.InstructionIndex+i < len(comp.PuzzleInput); i++ {
// grab the mode with a mod, last digit
mode := instruction % 10
instruction /= 10
switch mode {
case 1: // immediate mode, the index itself
paramIndexes[i-1] = comp.InstructionIndex + i
case 0: // position mode, index will be the value at the index
paramIndexes[i-1] = comp.PuzzleInput[comp.InstructionIndex+i]
}
}
return opcode, paramIndexes
}