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2016-day19: circular LL for removing elves from a table
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@@ -0,0 +1,77 @@
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package main
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import (
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"flag"
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"fmt"
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"github.com/alexchao26/advent-of-code-go/cast"
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"github.com/alexchao26/advent-of-code-go/util"
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)
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func main() {
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var part int
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flag.IntVar(&part, "part", 1, "part 1 or 2")
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flag.Parse()
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fmt.Println("Running part", part)
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ans := elephant(util.ReadFile("./input.txt"), part)
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fmt.Println("Output:", ans)
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}
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// LLNode represents an elf
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type LLNode struct {
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elfNum int
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presents int
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next *LLNode
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}
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func elephant(input string, part int) int {
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startingElves := cast.ToInt(input)
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root := &LLNode{
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elfNum: 1,
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presents: 1,
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}
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iter := root
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for i := 2; i <= startingElves; i++ {
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iter.next = &LLNode{
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elfNum: i,
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presents: 1,
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}
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iter = iter.next
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}
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iter.next = root
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if part == 1 {
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for root.next != root {
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root.presents += root.next.presents
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root.next = root.next.next
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root = root.next
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}
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return root.elfNum
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}
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// initialize a pointer to the node before the node across from the start
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// need the node before b/c removing a node is like reassigning beforeNode.next
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// if there are an odd number of starting elves, this points to the first one
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// which is also the one of "the left."
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isOddLength := startingElves%2 == 1
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beforeAcross := root
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for i := 0; i < startingElves/2-1; i++ {
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beforeAcross = beforeAcross.next
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}
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for root.next != root {
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root.presents += beforeAcross.next.presents
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// remove beforeAcross node
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beforeAcross.next = beforeAcross.next.next
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// if odd number of total nodes, beforeAcross node skips the node
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// that was previously the "right" side of the across pair
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if isOddLength {
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beforeAcross = beforeAcross.next
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}
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isOddLength = !isOddLength
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root = root.next
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}
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return root.elfNum
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}
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